Math, asked by anandshree46, 11 months ago

ages of roopa and her sister is in ratio 3 : 2 after 5 years the ratio becomes 4 :
3 find their present ages ​

Answers

Answered by manushri81
21

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Answered by Sauron
42

Answer:

Roopa is 15 years old and her sister is 10 years old.

Step-by-step explanation:

Given :

Ratio of present ages of Roopa and her sister = 3 : 4

Ratio of ages after 5 years = 4 : 3

To find :

Their present ages

Solution :

Let the present ages be -

  • Roopa as 3x
  • Her sister as 2x

\green{\boxed{\green{\boxed{\red{\sf{\frac{3x + 5}{2x + 5} =  \frac{4}{3}}}}}}}

 \sf{\implies} \: \dfrac{3x + 5}{2x + 5} =  \dfrac{4}{3} \\ \sf{\implies} \: 3(3x + 5) = 4(2x + 5) \\   \sf{\implies} \: 9x + 15 = 8x + 20 \\  \sf{\implies} \: 9x - 8x = 20 - 15 \\  \sf{\implies} \: x = 5

Value of 3x

 \sf{\implies} \: 3(5) \\  \sf{\implies} \: 15

Roopa's present age = 15 years

\rule{300}{1.5}

Value of 2x

 \sf{\implies} \: 2(5) \\  \sf{\implies} \: 10

Her sister's present age = 10 years

\therefore Roopa is 15 years old and her sister is 10 years old.

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