Question

Ages of Roopa and her sister is in ratio3.2.
after 5 years, ratio becomes 4:3. Find their present
ages​

Answer 1

Answer:

Hey mate

After 5 years Roopa's age = 3x+5

After 5 years her sister's age =2x+5

A/Q

3x+5/2x+5=4/3

=>3(3x+5)=4(2x+5)

=>9x+15 =8x +20

=>x= 5

Hence, present age of Roopa is 3×5=15 years

and present age of her sister is 2×5 = 10 years

Hope it will be helpful to uhh

Thanks (´∩｡• ᵕ •｡∩`)

Answer 2

Correct question :-

Ages of Roopa and her sister is in ratio 3 : 2. After 5 years, ratio becomes 4 : 3. Find their present ages.

Answer :-

Age of Roopa is 15 years and age of sister is 10 years.

Explanation :-

Ratio of ages of Roopa and her sister = 3 : 2

Let the ages of the Roopa and her sister be '3x' years and '2x' years

After 5 years

• Age of Roopa = (3x + 5) years

• Age of sister = (2x + 5) years

Given

Ratio of ages of Roopa and sister after 5 years = 4 : 3

⇒ (3x + 5)/(2x + 5) = 4/3

By cross multiplication

⇒ 3(3x + 5) = 4(2x + 5)

⇒ 9x + 15 = 8x + 20

⇒ 9x - 8x = 20 - 15

⇒ x = 5

Age of Roopa = 3x = 3(5) = 15 years

Age of sister = 2x = 2(5) = 10 years

∴ age of Roopa is 15 years and age of sister is 10 years.