Question

Ages of two persons differ by 16 years. if 6 year ago, the elder one be 3 times as old the younger one, find their present age

Answer 1

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Let the age of younger person be x

Thus, the age of the elder person is (x+16),

Their ages 6 years ago,

$3(x - 6) = (x + 16 - 6) \\ \\ = > 3x - 18 = x + 10 \\ \\ = > x = 14$

The age of the elder person will be (x+16) = 14 + 16 = 30

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Answer 2

Question:

Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age.

Answer:

Let the age of younger person be x.

It is just an assumption to make our calculations easy, you may take any other letter as variable.

Age of elder person - Age of younger person = 16 years

Age of elder person - x = 16

Age of elder person = x + 16

6 years ago,

Age of elder person = x + 16 - 6 = x + 10

A/Q,

6 years ago,

Age of younger person = x - 6

Age of elder person = 3 * Age of younger person = 3( x - 6 )

So,

x + 10 = 3( x - 6)

x + 10 = 3x - 18

3x - x = 18 + 10

2x = 28

x = 28/2

x = 14 years

Age of younger person = x = 14 years

Age of elder person = x + 16 = 14 + 16 = 30 years

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