Question

ages.
Two years ago, father was three times as old as his son and two years hence, twice
his
age
will be equal to five times that of his son. Find their present ages.
​

Answer 1

=> Let us consider

=> Son's ages = x

=> Two years ago son age = x - 2

=> His father age at that time = 3 ( x- 2 )

=> Present age of father = 3x - 6 + 2

=> The present age of father = 3x + 4

=> Two year hence father age = 3x - 4 + 2

=> Two years hence father age = 3x - 2

=> Two years hence son age = x + 2

Given :-

=> 5 × ( x + 2 ) = 2 × ( 3x - 2 )

=> 5x + 10 = 6x - 4

=> x = 14

Son present age x = 14 years.

Father present age = ( 3 × 14 ) - 4

Father present age = 38 years.

I hope this will help you dear..

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