Question

aggregate of even numbers from 200 to 300​

Answer 1

Answer:

hope it help ...................

Answer 2

Answer:

12750

Step-by-step explanation:

first even number from 200 to 300 is 200 = a

last even number from 200 to 300 is 300 = l

d = 2 difference between two even number

number of terms

an = a + (n-1)d

300 = 200 + (n-1)2

300 = 200 + 2n - 2

300 = 198 + 2n

300 - 198 = 2n

102 = 2n

n = 102/2 = 51

Sn = n/2 (2a + (n-1)d)

$= \frac{51}{2} (2(200) + (51 - 1)2) \\ = \frac{51}{2} (400 + 50(2)) \\ = \frac{51}{2} (400 + 100) \\ = \frac{51}{2} \times 500 \\ = 51 \times 250 \\ = 12750$

hope you get your answer