Question

ah 200% more efficient than B file it takes 60 days less than B to finish the work in how many days will they finish the work together​

Answer 1

answer:

Step-by-step explanation:

question:

ah 200% more efficient than B file it takes 60 days less than B to finish the work in how many days will they finish the work together

lesson take 'n':

Let A takes ′n′ days to paint the room.

So B will take 3n days to paint the room.

⇒3n−n=60 or n=30

⇒A takes 30 days and B takes 90 days.

A & B will do       301+901=904=452 work in a day.

So,they will complete the work in 245=2221days.

Hence, option C is the correct answer.

Answer 2

A and B 40 days to finish the work together.

Given:

A is 200% more efficient than B. This means that A can do the work twice as fast as B. Therefore, A will take x/2 days to finish the work.

To Find:

A + B = ? (in days)

Solution:

Let's assume that B takes x days to finish the work.

According to the problem, A is 200% more efficient than B. This means that A can do the work twice as fast as B. Therefore, A will take x/2 days to finish the work.

The problem also states that A takes 60 days less than B to finish the work. This means that the time difference between A and B is 60 days. We can set up an equation to represent this:

x - (x/2) = 60

Simplifying this expression, we get:

x/2 = 60

Multiplying both sides by 2, we get:

x = 120

Therefore, B takes 120 days to finish the work.

To find out how long it will take for A and B to finish the work together, we can use the following formula:

1/T = 1/A + 1/B

where T is the time it takes for A and B to finish the work together.

Substituting the values we have found, we get:

1/T = 1/(x/2) + 1/x

1/T = 2/x + 1/x

1/T = 3/x

Multiplying both sides by x, we get:

x/T = 3

Dividing both sides by 3, we get:

T = x/3

Substituting x = 120, we get:

T = 120/3 = 40

Therefore, it will take A and B 40 days to finish the work together.


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