Physics, asked by toxictanishk, 1 year ago

Ahall A is thrown up vertically with speed u. At the same
instant another ball B is released from rest at a heighth
vertically above the point of projection of A. Taking the
moment of projection as t = 0 and acceleration due to
gravity is 'g', answer the following questions,
21 At any time instant t, the magnitude of relative
acceleration of A with respect to B is
(1) g
(2) 2g
(3) -2g
(4) Zero
22. At any time instant t, the speed of A relative to Bis
(1) u
(2) 4- 2gt
(3) √u-2gt
(4) u-gt
23. The separation between the bodies at any time
instant t is
(1) h
(2) h-ut
(3) h-ut + gt²/2
(4) h-ut + gt²​

Answers

Answered by empathictruro
17

Answer:

Acceleration of body A= -g (since, it is moving upward)

Acceleration of body B= g (since, it is moving downward)

Acceleration of A wrt B = acceleration of A- acceleration of B

                                       = -2g

Speed of A at any time t= u-gt

Speed of B at any time t =gt

speed of A wrt to B = speed of A -speed of B = u-2gt

Height of A at any time t = ut- gt²/2

Height of B at any time t = h -ut

Seperation between the bodies= h-ut-ut-gt²/2

    =h-2ut-gt²/2

Answered by Shantanu520
58

Answer: this will help you

Explanation:

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