Question

Ahemispherical bowl is made of steel 0.25cm thick. The inner radius of the bowl is 5cm
22
Find the outer curved surface area of the bowl ​

Answer 1

Answer:

Step-by-step explanation:

Let the Inner radius of hemispherical bowl = 5 cm Thickness of the bowl = 0.25 cm ∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm = 5.25 cm Outer CSA of hemispherical bowl = 2πr2 = 2 x 22/7 x (5.25 cm)2 = 173.25 cm2 Therefore, the outer curved surface area of the bowl is 173.25 cm2.

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Answer 2

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$\small\bold{Inner \: radius \: of \: the \: bowl \: = }$ 5cm

$\small\bold{Thickness \: of \: the \: steel \: =}$ 0.25cm

$\small\bold{Outer \: radius \: of \: the \: bowl \: =}$ 5+0.25=5.25cm

$\small\bold{Outer \: Curved \: surface \: of \: the \: hemispherical \: bowl \: =}$ 2πr²

= 2× $\large\dfrac{22}{7}$ × (5.25)² = 172.25 cm²

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