Question

ahmad and Daryl had an equal amount of money at first. ahmad's father gave him another $180 and Daryl spent $254. Ahmad then had 4 times as much as Daryl. How much money did each of tjem have at first ?​

Answer 1

Step-by-step explanation:

ANSWER:-

Given that:-

• Ahmad and Daryl had equal amount of money
• Ahmad's father gave $ 180, Daryl spent $ 254
• Ahmad then has 4 times as much as Daryl.

Concept:-

Linear equations and cases

Let's Do!

Let the amount of money which Ahmad and Daryl had be x.

So, next step is ;-

1. Ahmad has money (x+180)
2. Daryl has money (x-254)

So, the equation is :-

$\rm{x+180 = 4(x-254)}$

$\rm{x+180 = 4x-1016}$

$\rm{1016+180 = 4x-x}$

$\rm{3x = 1196}$

$\rm{x = \dfrac{1196}{3}}$

$\rm{x = 398.66 \ Dollar}$

So, $ 398.66 is the required sum they had earlier.

Answer 2

$\huge \bf Given$

ahmad and Daryl had an equal amount of money at first. ahmad's father gave him another $ 180 and Daryl spent $254. Ahmad then had 4 times as much as Daryl.

$\huge \bf To \: Find$

Amount both have

$\huge \bf Answer$

Let the money of both be y

Now,

Equation formed

y + 180 = 4(y - 254)

y + 180 = 4y - 1016

4y - y = 1016 + 180

3y = 1016 + 180

3y = 1196

y = $ 398.66