Ahmed is painting the walls and ceilings of a cuboidal hall with the Length breadth and height of 25m, 12 m and 8 m, respectively. From each can of paint 200 m square of area is painted.
How many cans will she need to paint the room. plz tell the answer
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Answered by
18
* is used for multiplication below
area of the four wall
= 2*(l*b) + 2*(b*h)
i.e.
= 600 + 192
= 792
area of the ceiling
= l*b
= 300
total area to be painted
= 300+792
=1092
therefore, no of cans required
1092/ 200
= 5.46
~ 6
area of the four wall
= 2*(l*b) + 2*(b*h)
i.e.
= 600 + 192
= 792
area of the ceiling
= l*b
= 300
total area to be painted
= 300+792
=1092
therefore, no of cans required
1092/ 200
= 5.46
~ 6
Rohitrocker52:
were you in Ncs vizag
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36
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