Question

Ahmed is painting walls and ceiling of the cuboidal hall with the dimension

25mx12mx8m.From each can of paint 200m2 of area is painted. How many cans

of paint will he need to paint the room.​

Answer 1

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Area of the four wall

= 2*(l*b) + 2*(b*h)

i.e.

= 600 + 192

= 792

area of the ceiling

= l*b

= 300

total area to be painted

= 300+792

=1092

therefore, no of cans required

1092/ 200

= 5.46

~ 6

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