Ahmed purchased a house with a cuboidal hall with a length, breadth, and height of 25
m, 12 m, and 8 m respectively with a rectangular pool that has a swimming area that
is 75 feet long by 25 feet wide and is 3 feet deep. , having four cylindrical pillars of a
radius of 14 m and a height of 3 m.
a) Find the total surface area of the room.
b) Find the volume of the pool.
c) What is the lateral surface area of the four cylindrical pillars?
Answers
Answered by
0
Answer:
a :- 1192m
b :- 5625m
c :- 264m
Step-by-step explanation:
a- Total surface area of cuboidal hall = 2(lb+bh+hl)
= 2(25×12+12×8+8×25)
=2(300+96+200)
=2×596
=1192m²
b- volume of rectangular pool = l×b×h
= 75×25×3
=5625 feet
c- lateral surface area of the one cylindrical pillars = 2πrh
= 2×22/7×14×3
= 22×3
=66m
=66
four cylindrical pillars area = 66×4
= 264m²
hope this answer helps you
if yes then mark me as brainlist!
Similar questions