Question

Ahmed, who weighs 350.0 N, sits on the slope of a hill that descends at an angle of 60.0° from horizontal. What are the components of his weight parallel and perpendicular to the surface of the hill?

Answer 1

Answer:

Weight parallel to surface of the hill = 350×cos(60)

Weight perpendicular to surface of the hill = 350×sin(60)

Answer 2

I made a mistake in Component parallel to his weight, it is hill. Btw they both are parallel and perpendicular.