AHMEDABAD= -7, pALANPUR= 5, SURENDRANAGAR=?
Answers
AHMEDABAD= -7, pALANPUR= 5, SURENDRANAGAR= -37
Step-by-step explanation:
Giving the corresponding order number to each alphabet, that is
A=1, B=2,C=3,D=4,...........,Y=25 & Z=26 and applying addition and subtraction alternatively we get,
AHMEDABAD=1+8-13+5-4+1-2+1-4=-7
PALANPUR=16+1-12+1-14+16-21+18=5
Therefore the number corresponding SURENDRANAGAR is,
SURENDRANAGAR=19+21-18+5-14+4-18+1-14+1-7+1-18=37.
Answer:
The code would be -37.
Step-by-step explanation:
Given,
The code of FROG = 2116,
Since, we know that, in the English alpha bates the order from left to right is,
A, B, C, ......................................Z,
i.e. order of A = 1, order of B = 2.......so on,
So, the order of,
A= 1, H = 8, M= 13, E = 5, D = 4, B = 2, D = 5
Also, 1+8-13+5-4+1-2+1-4 = -7,
Again,
P = 16, L = 12, N = 14, U = 21, R= 18
And, 16+1-12+1-14+16-21+18 = 5,
By following these pattern,
The code for SURENDRANAGAR =19+21-18+5-14+4-18+1-14+1-7+1-18=-37
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