Math, asked by Anonymous, 1 year ago

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If A,B,C are the interior angle of triangle ABC, then show that -
Sin(B+C / 2) = Cos (A / 2)

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Answers

Answered by krushangivyas
7
hope it helps u
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Answered by Anonymous
11
A+B+C=180

So,

b+c=180-A

b+c/2=90-a/2 ( Dividing the L.H.S and R.H.S by 2)

sin(b+c/2)

= sin ( 90 -a/2) ( Substituting b+c/2 value)

= cos a/2

Hence Proved

hope \: helps

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