Question

✨Ahola brainlics✌❤✌
⭐Question in attachment⭐
☑Plz solve☺
Thanks...❤❤

Answer 1

⭐hey there!!

Given that:

➡ ∫ dx/√x+a - √x}

Now rationalization of denominator,

=>> 1/(√x+a - √x) × (√x+a + √x) /(√x+a +√x)

=> (√x+a + √x) /a ------------------(1)


Now intigrating expression (1)

= 1/a ∫(√x+a + √x ) dx

= 1/a { ∫√(x+a) dx + ∫√x dx }

= 1/a ( 2/3 (x+a) ³/2 + 2/3 x³/2 )

=> 2/3a { (x+a)³/2 + x³/2 } ans


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⭐Hope it will help u

Answer 2

Answer:

bhai password bhul chuki hu bhool jao mujge sorry