Question

Ahola ❤☺

One litre sample of sea water is found to contain 5.8 * 10^-3g of dissolved oxygen, Calculate the concentration of disolved oxygen in a sea water in ppm if the density of sea water is 1.03 g/cm^3 ​

Answer 1

Answer: 5.63 g

Given,

Density of the sea water = 1.03 g $cm^{-3}$

As we all know,

Density = $\frac{mass}{volume}$

Here,

Mass of 1 litre = 1000$cm^{3}$ of the sea water

Mass = volume × density (from above)

        = 1000 $cm^{3}$ × 1.03 g $cm^{-3}$  

         = 1030 g

Thus,

1030 g of sea water contain 5.8 ×$10^{-3}$ g of dissolved oxygen.

Therefore,

Mass of oxygen present in $10^{6}$ (one million) g of sea water =

=> $\frac{5.8* 10^{-3} }{1030}$ × $10^{6}$

=> 5.63 g

Hence, the concentration of dissolved $O_{2}$ in sea water is 5.63 g