Question

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Solve question no. 19
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Answer 1

Q : One Gram of the acid C6H10O4 requires 0.768 g of KOH for complete neutralization.
How many neutralizable hydrogen atoms are in this molecule.

Final Answer :There are two neutralizable H atoms.

Formula Used :
1) No. of moles, = Given Mass /Molar Mass
2) No.of equivalents, = No. of moles * Valency Factor

Given :
1) Given Mass of C6H10O4 = 1 g
Molar Mass of C6H10O4 = 12*6+10*2+16*4=146g
Given Mass of KOH = 0.768 g
Molar Mass of KOH = 39+ 16 +1 = 56 g

Steps:
1) No. of acidic Hydrogen /neutralizable H atoms in acid be 'n'.

Valency Factor of Acid C6H10O4 = n

There is only one basic HYDROXIDE in KOH.
=> Valency Factor of KOH = 1

2) By Equivalent concept,
no. of equivalents of C6H10O4 = no. of equivalents of KOH
=> no. of moles * Valency Factor(C6H10O4)=
no. of moles of KOH
$= > n \times \frac{1}{146} =1 \times \frac{0.768}{56} \\ = > n = \frac{146 \times 0.768}{56} \\ = > n = 2 \: \: (approx.)$

Hence, No. of Neutralizable or unusable H in C6H10O4 are 2 .

Answer 2

Answer:

The acceleration which is gained by an object because of gravitational force is called its acceleration due to gravity. ... The acceleration due to gravity at the surface of Earth is represented by the letter g. It has a standard value defined as 9.80665 m/s2 (32.1740 ft/s2).