Question

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Answer 1

$\bold{Answer :}$

Now,

∫ (1 + cosx)/sinx dx

= ∫ 1/(sinx) dx + ∫ (cosx)/(sinx) dx

= ∫ cosecx dx + ∫ cotx dx

= log (cosecx - cotx) + log (sinx) + log (c), where (log c) is integral constant

= log {(cosecx - cotx) sinx c}

= log [c {1/(sinx) - (cosx)/(sinx)} sinx]

= log {c (1 - cosx)}, which is the required integral

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Answer 2

Answer:

Step-by-step explanation:

Hope you understood