Question

Aiden, Beck and Chris share 6 identical candies. If each of them gets at least one candy, there are 10 methods. How many method(s) is are there to share the candies if someone may get no candies?

Answer 1

Answer:

1st case : let one of them get 0 candies then,ways in which candies can be distributed:1×6×5(NOTE: there is only 1 way in which one of them van be given 0 candies)

thus total ways=30

2nd case:all of them be given atleast 1 candy then, total no. of ways=6×5×4=120

thus, total no. of ways=120+30=150

Answer 2

19

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