Question

aion help me in this question i m getting a little problem

Answer 1

Hey ! Brother 

We have given three identical spherical conductors . P, Q and R . 
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Charges on the conductors are as follows -10 μC , 40μC and q. 
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Now first we calculate Force of attraction between P and Q . 

F = κ $\frac{ 10 . 40}{ d^{2} }$   

F = 400 κ / d²-------------------------------------- ( 1 ) 
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Case : 1 
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Now the P and Q touched to each other 

The both conductors identical so there Charges now Become equal . 
=  (40 -10 ) / 2 
= 15 μC

Case :2 

Now, Body Q and R touched . 

It means that they acquire same charges too . 

=( 15 +q ) / 2

Now They again parted away ....

4F = { κ $\frac{ ( 15 +q )}{ 2}$ $\frac{15 + q}{2}$ } / d²____(2)

Put the value of F in the above equation ( 2 ) 

4 x  400 κ / d² = κ{ ( 15 + q) /2 }² / d²

1600 = { ( 15 + q) /2 }² 

Taking root both side . 

40 = ( 15 + q ) / 2

80 = 15 + q 

q= 80 -15 

q = 65 μC ( d )

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Hope you get it bro : ]

Answer 2

Explanation:

___Hope this'll help U ✌ ✌