Chemistry, asked by gawandekanchan2, 9 months ago

AIPMT 2008
The correct order of decreasing second ionisation
enthalpy of Ti(22), V(23), Cr(24) and Mn(25) is :
e popust
(1) Mn > Cr > Ti>V
(2) Ti> V > Cr > Mn
(3) Cr > Mn > V> Ti
(4) V> Mn > Cr > Ti​

Answers

Answered by deepikagn554
1

Answer:

Cr>Mn>V>Ti third option

Explanation:

IE value increases towards right Cr+ has 3d5 configuration which is more stable

Just looking at the electronic configuration we can answer these type of questions

Similar questions