Question

AIPMT Mains-2011
Consider the following processes :-
AH(kJ/mol
17 AB
+150
3B → 2C+D
-125
E + A + 2D
+350
For B + D E + 2C. AH will be :
(1) 325 kJ/mol
(2) 525 kJ / mol
13) -175 kJ/mol
(4) -325 kJ/mol
​

Answer 1

Answer:

...

=-175

Explanation:

b+d>>e+2c

now 2(eq1) + eq2 -eq3

=2(150)-125-350

=300--475

=-175