Question

air at a temperature of 25 degree Celsius and pressure 760 mmHg has a relative humidity of 75% what is the molal humidity of air ( vapour pressure of water at 25 degree Celsius is 2.5 kN/m2​

Answer 1

Answer:

21.6mm

Explanation:

Given,

Air at a temperature of 25 degree Celsius and pressure 760 mmHg has a relative humidity of 75%.

To Find,

The molal humidity of water.

Concept:

Molal Humidity - Molal Humidity is defined as the ratio of moles of vapour (condensable) to the moles of dry(non-condensable) gas.

Moles of Water Vapour - (Measured in Mole) - Moles of Water Vapour is defined as the amount (K mol) of water vapour that is present in the air.

Moles of Bone Dry Air - (Measured in Mole) - Moles of Bone Dry Air is a sample of air that has no water. A definition of dry air is air that has a low relative humidity.

% relative humidity = $partial pressure of waterX\frac{100}{aqueous tension}$

⟹80= partial pressure of water × $\frac{100}{27}$

Hence, the partial pressure of water is 21.6 mm.

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Answer 2

Answer:

0.03

Explanation:

Using PV=NRT

here p = pressure

v = volume

n = moles

r = universal gas constant

t = temperature

values p = 760mm of hg = 1 atm

T = 25 c = 273 +25 = 298 K

relative humidity = density of gas 1/density of gas2

The absolute humidity is also referred to as the humidity ratio and is represented as AH = 0.6207*Hm or Absolute Humidity = 0.6207*Molal Humidity. Molal Humidity is defined as the ratio of moles of vapour(condensable) to the moles of dry(non-condensable) gas.

now vapour density = molecular weight/2

putting the values = n = pv/rt

n = 0.03

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