Question

Air conatins 20% o2 by volume.How many



c.C. Of air will be requielred for oxidation of 100cc of acetylene

Answer 1

2 C2H2 moles will react with 5 moles of Oxygen

1 C2H2mole will react with 5/2 moles of O2

If we suppose that the gases are under standard conditions, then

22.4LC2H2 will react with 52×22.4LO2

This means that:

0.1LC2H2 will react with 52×0.1LO2

0.1LC2H2 will react with 52×0.1×5L of air

So, the volume of air is 1.25L=1250cc

Answer 2

2C2H2+5O2⟶4CO2+2H2O2CX2HX2+5OX2⟶4COX2+2HX2O

From stoichiometric calculations:

2 C2H2CX2HX2 moles will react with 5 molecules of oxygen

1 C2H5⟶5/2CX2HX5⟶5/2 moles of O2OX2

22.4 l22.4 l C2H2⟶CX2HX2⟶ 5/2×22.4 l5/2×22.4 l of O2OX2

1 volume of air -> 0.2 (20/100) volume of oxygen

Now the only thing I don’t know is how to convert the volume into liters so that I can find the correct answer.

mark as brainliest please