Question

Air contains 20 perxent by volume of oxygen the volune of air required

Answer 1

Answer:

1250cc

Explanation:

2C2H2  +      5O2     =4CO2+2H2O

2(22.4)l       5(22.4)l

44800ml    112000ml

44800ml of ether reacts with 11200ml of O2

hence,100ml ether will react with

                                 =112000/44800*100

                                  =250ml

now,X ml of air contains 20% O2

    hence 20/100*x=250

       X=2500/2

       X=1250cc

      tq.........