Question

Air contains 79% N2 and 21%O2 by volume .If the barometer pressure is 750 mmHg,then partial prassure of oxygen is??

Answer 1

You can easily calculate the partial pressure of oxygen keeping in mind the definition of partial pressure.

First of all You have the find out the mole fraction of the oxygen and we know that mole fraction can be calculated from percentage composition of the gas divided by the total percentage of all gases 
So here oxygen is 21% = mole fraction of 21 % oxygen =21/100 = 0.21 
Here total pressure is give which is =750mm of Hg 
Partial pressure of oxygen will be = 750 *0.21  = 157.5 mm of Hg .
So partial pressure of oxygen will be 157.5 mmHg

Answer 2

Answer:

157.5 mm of hg

Explanation:

mole fraction of o2 = 0.21

partial pressure = mole fraction x total pressure

therefore partial pressure of o2 = 0.21 x 750 = 157.5 mm of hg

Thank you