air contains nearly 20% oxygen by volume. The ratio by volume of oxygen to air at STP required for complete combustion of 20 gram benzene is
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Answer:
2C2H2+5O2⟶4CO2+2H2O
From stoichiometric calculations:
2 C2H2
moles will react with 5 molecules of oxygen
1 C2H5⟶5/2 moles of O2
22.4 l C2H2⟶ 5/2×22.4 l of O2
1 volume of air -> 0.2 (20/100) volume of oxygen
Now the only thing I don’t know is how to convert the volume into liters so that I can find the correct answer.
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Explanation:
your question doesn't make any sense you are saying that oxygen molecule are better than the carbon Dai oxide is the molecules and doesn't even have molecules it has degrees and Celsius you are so
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