Question

Air enters an insulated nozzle at 200 kpa and 950 k and discharged at 70 kpa

Answer 1

IDK by this formula you will come to know

Answer 2

Given that,

Initial pressure = 200 kPa

Temperature = 950 k

Final pressure = 70 kPa

Suppose, Find the maximum velocity obtained at the nozzle exit

We need to calculate the final temperature

Using formula of temperature

$\dfrac{T_{2}}{T_{1}}=(\dfrac{P_{2}}{P_{1}})^{\frac{\gamma-1}{\gamma}}$

Put the value into the formula

$T_{2}=(\dfrac{70}{200})^{\frac{1.4-1}{1.4}}\times950$

$T_{2}=703.81\ K$

We need to calculate the maximum velocity obtained at the nozzle exit

Using formula of velocity

$v=\sqrt{2\times C_{p}\times \Delta T\times}$

Put the value into the formula

$v=\sqrt{2\times1.007\times(950-703.81)}$

$v= 22.26\ m/s$

Hence, The maximum velocity obtained at the nozzle exit is 22.26 m/s