Question

air expands from 5 litres to 10 litres at 2 atm pressure. external work done is

Answer 1

Work W  done is defined as integral of  P dV  =  P (V2 - V1)
           as pressure is constant.

  W = 2 * 1.013 * 10⁵ N/m²  (10 - 5) * 10⁻³  m³
       = 1.013 kJoules

Answer 2

Answer:

Given that,

Vf=90l (convert litres into meter so multiply with 10*-3), Vi=40l(40×10*-3), P=8atm(1atm=10*5)[*means 10 power - 3]

Explanation:

W=P(Vf-Vi)

=P(90×10*-3×40×10*-3)

=8×10*5×50×10*-3

=400×10*5×10*-3

=4×10*4 J

Hope it helps you