Air has refractive index 1.0003. The thickness of air column, which will have one more wavelength of yellow light (6000 a) than in the same thickness of vacuum, is
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Hey buddy,
◆ Answer-
t = 2 mm
◆ Explanation-
# Given-
μ = 1.0003
λ = 6000 A = 6×10^-7 m
n' = n+1
# Solution-
Let be the thickness of air column.
n = t/λ
n' = t/λ'
We have-
n' = n + 1
t/λ' = t/λ + 1
t(1/λ' - 1/λ) = 1
Putting λ' = λ/μ
t = λ/(μ-1)
t = (6×10^-7) / (1.0003-1)
t = (6×10^-7) / (3×10^-4)
t = 2×10^-3 m
t = 2 mm
Thickness of air column will be 2 mm.
Hope this helps you...
◆ Answer-
t = 2 mm
◆ Explanation-
# Given-
μ = 1.0003
λ = 6000 A = 6×10^-7 m
n' = n+1
# Solution-
Let be the thickness of air column.
n = t/λ
n' = t/λ'
We have-
n' = n + 1
t/λ' = t/λ + 1
t(1/λ' - 1/λ) = 1
Putting λ' = λ/μ
t = λ/(μ-1)
t = (6×10^-7) / (1.0003-1)
t = (6×10^-7) / (3×10^-4)
t = 2×10^-3 m
t = 2 mm
Thickness of air column will be 2 mm.
Hope this helps you...
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