Question

Air is compressed steadily by a 5-kw compressor from 100 kpa and 17 c to 600 kpa and 167 c at a rate of 1.6 kg/min. Determine the entropy change

Answer 1

Answer:

I can't answer this question because I have not any idea about this

Explanation:

I can't answer this question because I have not any idea about this

Answer 2

Answer: The entropy change is 0.00254 kW/K.

Explanation:

The given data is as follows.

     $T_{1} = 17^{o}C$ = (17 + 273) K = 290 K,

     $T_{2} = 167^{o}C$ = (167 + 273) K = 440 K,

     $p_{1}$ = 100 Kpa,       $p_{2}$ = 600 Kpa

Now, we will calculate the rate of change in entropy as follows.

 $\Delta S = m[c_{p} ln(\frac{T_{2}}{T_{1}}) - R ln(\frac{p_{2}}{p_{1}})$

          = $\frac{1.6}{60}[1005 ln(\frac{440}{290}) - (287) ln(\frac{600}{100})$    

          = $\frac{1.6}{60} \times (418.98 - 514.23)$

          = -0.00254 kW/K

Thus, we can conclude that the entropy change is 0.00254 kW/K.