Question

air is contained in a rigid container has a pressure of 0.5 bar vacuum. if the atmospheric pressure is 740 mmHG, and the density of mercury is 13.59 g/cm^3, determine the absolute pressure of the container, in a bar

Answer 1

Answer:

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Answer 2

Answer:

The absolute pressure of the container in a bar is 0.4865 bar

Explanation:

Gauge pressure:

• The pressure as compared to atmospheric pressure is known as gauge pressure.
• For pressures above atmospheric pressure, gauge pressure is positive; for pressures below it, it is negative.

Absolute pressure:

• Gauge pressure and atmospheric pressure add up to absolute pressure.

Atmospheric pressure:

• The force that the air column above the Earth exerts on its surface is known as atmospheric pressure.
• The weight of the air above the surface of the Earth is what creates atmospheric pressure.

Absolute pressure is given

Absolute pressure = atmospheric pressure + gauge pressure

Absolute pressure

Atmospheric pressure = density of mercury x acceleration due to gravity x height of column of mercury.

Density of mercury = 13.59

Acceleration due to gravity = 9.81

Height of the column of mercury = 740 mm

$P_{atm} = p.g.h$

= 13.59 × 0.001 × 9.81 × 74

= 0.9865 bar

Atmospheric pressure = 0.9865 bar

We know that,

Absolute Pressure = Gauge pressure + Atmospheric Pressure

Atmospheric pressure = 0.9865

Gauge pressure = -  0.5

Therefore absolute pressure

$P_{a} = P_{atm} + P_{g}$

   = 0.9865 + (-05)

   = 0.4865 bar

Final answer:

The absolute pressure of the container in a bar is 0.4865 bar

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