Air is straming past a horizontal air plane wing sych that its speed is 120m/s over the upper surface and 90m/s at the lower surface. if the density of air iss 1.3 kg per m^3 and the wing is 10m long and has and average width of 2m , then the difference of the pressure on the two sides of wing of
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P' - P = (1/2)×density of air×((V')^2_(V)^2)puting the values in the formula we get diff in pressure=4095
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Explanation:
answer is 4095 Pascal
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