Math, asked by jaideva24297, 10 months ago

air temperature in the Rajasthan desert can reach 46 degree celsius. what is the velocity of sound in air at that temperature?(Vo=331ms*-1)​

Answers

Answered by aristeus
17

Answer:

So the velocity of sound at 46° will be 357.77 m/sec

Step-by-step explanation:

We have given that temperature is T = 46°C

Normal velocity is given as v_o=331m/sec

We have to find the velocity of sound at 46°C

We know that velocity of sound at any temperature is given by

v=v_0\sqrt{1+\frac{T_C}{273}}=331\times \sqrt{1+\frac{46}{273}}=357.77m/sec

So the velocity of sound at 46° will be 357.77 m/sec

Answered by lublana
7

The velocity of sound at that temperature =357.8 ms^{-1}

Step-by-step explanation:

Temperature=46^{\circ}

Normal velocity=v_0=331ms^{-1}

We know that

Speed of sound wave as function of temperature is given by

v=v_0\sqrt{1+\frac{T}{273}}

Where v_0=Normal velocity

T=Temperature(in degree Celsius)at which velocity to find  

Substitute the values then we get

v=331\sqrt{1+\frac{46}{273}}

v=357.8 ms^{-1}

Hence, the velocity of sound at that temperature =357.8 ms^{-1}

#Learns more:

htbrainly.in/question/90766tps://

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