Ais 4 times as fast as B and is therefore able to finish a work in 45 days less than B find the time in which they can work together
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Total time taken by both=12 days
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Suppose B can do a work in X days.
Therefore A can do it in X /4days .
X- X/4 = 45 days. (4X-X)/4 = 45 days. Then X=60 days.
The work B can do in 60 days.
The work A can do in 15 days.
B can do in 1 day = 1/60 part.
A can do in 1 day = 1/15 th part. Both jointly can do in 1 day = 1/60+ 1/15 = 1/12 part.
Therefore A+ B can finish that work in 12 days. Ans.
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