Question

ऐसे ऑन राष्ट्र चिन्ह इन संस्कृत​

Answer 1

sorry not able to understand the question

Answer 2

Answer:

OA = OB [Radii of the same circle] ∴ Point O is equidistant from the endpoints A and B of seg AB. ∴ Point O lies on the perpendicular bisector of AB. [Perpendicular bisector theorem] Similarly, we can prove that, Point O lies on the perpendicular bisector of BC. ∴ Point O is the point of intersection of perpendicular bisectors of AB and BC (i.e., circumcentre of ∆ABC) ……… (i) Now, suppose that the points A, B, C are collinear. Then, the perpendicular bisector of AB and BC will be parallel. [Perpendiculars to the same line are parallel] ∴ The perpendicular bisector do not intersect at O. This contradicts statement (i) that the perpendicular bisectors intersect each other at O. ∴ Our supposition that A, B, C are collinear is false. ∴ Points A, B and C are non collinear points.Read more on Sarthaks.com - https://www.sarthaks.com/854600/prove-that-any-three-points-on-a-circle-cannot-be-collinear