Science, asked by muteeb786, 9 months ago

Aisha dropped an object of mass 4 Kg from a height of 10m.
The object has a speed of 0 m/s at position A and is at a height
of 10m above the ground. At position B, the object is om above
the ground. At position C, the object is 4m above the ground.
At point D, the object is mere picometer ( almost at O meter height)
above the ground. Assume negligible air resistance throughout
the motion. Use this information to fill in the table. (g=10m/s2)​

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Answered by jyotitailor500
2

Answer:

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Answered by BrainlyPrince727
0

Given :-  

The object has a speed of 0 m/s at position A and is at a height  

A  of 10m above the ground.  

 

To find :-  

Velocity & time taken to reach at B , C & D

 

Solution :-  

At  t = 0    position  A  - 10 m above ground    velocity =  0

PE = mgh = 4 * 10 * 10 = 400 Joule

KE =(1/2)mv² = 0

At position B  - 6 m above ground distance covered  (10 - 6) = 4 m

S = ut + (1/2)at²  

u = 0

a = g = 10

=> 4 = (1/2)(10)t²

=> t = √0.8  =  0.9 sec

V = U  + at   =  9 m/s

PE = 4 * 10 * 6 ≈ 240 joule  

KE = 400 - 240 ≈ 160 Joule

At position C  - 4 m above ground distance covered  (10 - 4) =6 m

S = ut + (1/2)at²  

u = 0

a = g = 10

=> 6 = (1/2)(10)t²

=> t = √1.2  ≈ 1.1 sec

V = U  + at   ≈  11 m/s

PE = 4 * 10 * 4 = 160 joule

KE = 400 - 160 = 240 Joule

At position D  - 0 m above ground distance covered  (10 - 0) =10 m

S = ut + (1/2)at²

u = 0

a = g = 10

=> 10 = (1/2)(10)t²

=> t = √2  = 1.4sec

V = U  + at   =  14 m/s

PE = 4 * 10 * 0 =  0 joule  

KE = 400  Joule

Position  Distance from ground  PE    KE     Time         Velocity

A                   10 m                        400   0        0  s             0 m/s

B                   6 m                          240  160     0.9 s           9 m/s

C                   4 m                          160   240     1.1 s            11 m/s

D                   0 m                          0       400    1.4 s           14 m/s  

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