Question

Aisha dropped an object of mass 4 Kg from a height of 10m.
The object has a speed of 0 m/s at position A and is at a height
A
of 10m above the ground. At position B, the object is 6m above
B
the ground. At position C, the object is 4m above the ground.
At point D, the object is mere picometer ( almost at 0 meter height)
С
above the ground. Assume negligible air resistance throughout
the motion. Use this information to fill in the table. (g=10m/s2)

solve pls and explain also pls it's very argent Very very argent pls solve​

Answer 1

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Given : The object has a speed of 0 m/s at position A and is at a height

A of 10m above the ground.

To find : Velocity & time taken to reach at B , C & D

Solution:

At t = 0 position A - 10 m above ground velocity = 0

PE = mgh = 4 * 10 * 10 = 400 Joule

KE =(1/2)mv² = 0

At position B - 6 m above ground distance covered (10 - 6) = 4 m

S = ut + (1/2)at²

u = 0

a = g = 10

=> 4 = (1/2)(10)t²

=> t = √0.8 = 0.9 sec

V = U + at = 9 m/s

PE = 4 * 10 * 6 ≈ 240 joule

KE = 400 - 240 ≈ 160 Joule

At position C - 4 m above ground distance covered (10 - 4) =6 m

S = ut + (1/2)at²

u = 0

a = g = 10

=> 6 = (1/2)(10)t²

=> t = √1.2 ≈ 1.1 sec

V = U + at ≈ 11 m/s

PE = 4 * 10 * 4 = 160 joule

KE = 400 - 160 = 240 Joule

At position D - 0 m above ground distance covered (10 - 0) =10 m

S = ut + (1/2)at²

u = 0

a = g = 10

=> 10 = (1/2)(10)t²

=> t = √2 = 1.4sec

V = U + at = 14 m/s

PE = 4 * 10 * 0 = 0 joule

KE = 400 Joule

Position Distance from ground PE KE Time Velocity

A 10 m 400 0 0 s 0 m/s

B 6 m 240 160 0.9 s 9 m/s

C 4 m 160 240 1.1 s 11 m/s

D 0 m 0 400 1.4 s 14 m/s

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