aisha dropped an object of mass 4kg from a height of 10m.the object has a speed of 0m/s at position A and is at a height of 10m above the ground .At position B ,the object is 6m above the ground .At position C the object 4m above the ground .At point D,the object is mere picimeter (almost at 0 meter height)above the ground .Assume negligible air resistance throughout the motion.use this information to fill in the blanks (g=10/s)
position height(m) potential velocity v ep+ek 10
a 6
4
0
b
c
d energy(ep)
Answers
Answer:
10 m
Explanation:
object is just droped,that is with intial velocity =0
And after that it will gain velocity going down due to acceleration due to gravity...!
Given : The object has a speed of 0 m/s at position A and is at a height
A of 10m above the ground.
To find : Velocity & time taken to reach at B , C & D
Solution:
At t = 0 position A - 10 m above ground velocity = 0
PE = mgh = 4 * 10 * 10 = 400 Joule
KE =(1/2)mv² = 0
At position B - 6 m above ground distance covered (10 - 6) = 4 m
S = ut + (1/2)at²
u = 0
a = g = 10
=> 4 = (1/2)(10)t²
=> t = √0.8 = 0.9 sec
V = U + at = 9 m/s
PE = 4 * 10 * 6 ≈ 240 joule
KE = 400 - 240 ≈ 160 Joule
At position C - 4 m above ground distance covered (10 - 4) =6 m
S = ut + (1/2)at²
u = 0
a = g = 10
=> 6 = (1/2)(10)t²
=> t = √1.2 ≈ 1.1 sec
V = U + at ≈ 11 m/s
PE = 4 * 10 * 4 = 160 joule
KE = 400 - 160 = 240 Joule
At position D - 0 m above ground distance covered (10 - 0) =10 m
S = ut + (1/2)at²
u = 0
a = g = 10
=> 10 = (1/2)(10)t²
=> t = √2 = 1.4sec
V = U + at = 14 m/s
PE = 4 * 10 * 0 = 0 joule
KE = 400 Joule
Position Distance from ground PE KE Time Velocity
A 10 m 400 0 0 s 0 m/s
B 6 m 240 160 0.9 s 9 m/s
C 4 m 160 240 1.1 s 11 m/s
D 0 m 0 400 1.4 s 14 m/s
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