Aishwarya is five times her cousin's age. 12 years hence, she will be twice her cousin's
age. Find Aishwarya's and her cousin's ages.
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Answer:
Let A be Aishwarya's age
Let C be her cousin's age
Aishwarya is five times her cousin's age
equation i. A = 5*C
12 years hence, she will be twice her cousin's
equation ii. A+12 = 2 * (C+12)
Substituing equation i in equation ii
5*C + 12 = 2*C +24
3C = 12
C = 4
If C = 4 the A = 5 * 4 , therefore Aishwarya's age is 20
Answered by
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hey mate here is ur answer ...
let age of Aishwarya cousin=x
so, age of Aishwarya=5x
(A.T.Q.)
2(x+12)=5x+12
2x+24=5x+12
24-12=5x-2x
12= 3x
12÷3=x
4=x
hence age of Aishwarya cousin=x=4years
so, age of Aishwarya=5x=5×4=20years
hope it helps you mate
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