Ajay and his wife Reshmi appear in an interview for two vaccancies in the same post. The Probability of Ajay's selection is 1/7 and that of his wife Reshmi's selection is 1/5. What is the probability that only one of them will be selected?
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Answered by
2
Heyaa
Here is ur ans
<<<==============================>>>
only one of them will be selected) = p[(E and not F) or (F and not E)]
= P[(E∩F)∪(F∩E)]PE∩F∪F∩E
= P(E)P(F)+P(F)P(E)PEPF+PFPE
=1/7×4/5+1/5×6/7=2/7
Hope it helps u
Be brainly ;-) ❤❤❤
Here is ur ans
<<<==============================>>>
only one of them will be selected) = p[(E and not F) or (F and not E)]
= P[(E∩F)∪(F∩E)]PE∩F∪F∩E
= P(E)P(F)+P(F)P(E)PEPF+PFPE
=1/7×4/5+1/5×6/7=2/7
Hope it helps u
Be brainly ;-) ❤❤❤
Answered by
1
Two persons Ajay and Reshmi appared
Only one of them is selected
X (one Selected) = 1- [ X( both selected) + X (neither is selected) ]
= 1 - [ (1/35) + ( 4/5) (6/2) ]
= 1 - [1/35 + 24/35]
= 1 - [5/7]
= [2/7]
Therefore, Probability if only One off them will be selected = 2/7
If both of them selected, the probability = X (ajay & reshma) = [1/5] [1/7] = 1/35
HOPE THIS HELPS!
Only one of them is selected
X (one Selected) = 1- [ X( both selected) + X (neither is selected) ]
= 1 - [ (1/35) + ( 4/5) (6/2) ]
= 1 - [1/35 + 24/35]
= 1 - [5/7]
= [2/7]
Therefore, Probability if only One off them will be selected = 2/7
If both of them selected, the probability = X (ajay & reshma) = [1/5] [1/7] = 1/35
HOPE THIS HELPS!
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