Ajay and sita are two of Mr.kumars children.ajay has half as many brothers as
sisters.sita has as many brothers as sisters. Find the number of children Mr.kumar
has ?
Answers
By framing the equations and solving, we get the number of sons as 3 and the number of daughters as 4.
So, total children is 7.
the equations formed will be
X+0.5X=y
y+y=x
On solving these 2 you get
y=3
x=4
Ans=X+Y=7
Given :
Ajay and sita are two of Mr. kumars children
Ajay has half as many brothers as sisters
Sita has as many brothers as sisters
To Find :
Total number of children
Solution :
Let The number of boys = x
Let The number of girls = y
According to question
From statement I
Ajay has half as many brothers as sisters
i.e x + = y
Or, x + 0.5 x = y
Or, 1 . 5 x = y .............1
And
From statement II
Sita has as many brothers as sisters
i.e y + y = x
Or, 2 y = x ..............2
Solving eq 1 and eq 2
+ 2 x = y
i.e 2 y = 7 x
Or, Number of girls = sita + number of boys
= sita + 3
= 4
Number of boys = Ajay + half of sister
= Ajay + 2
= 3
So, From the condition it is clear that,
Total number of children = boys + girls
= 7