Ajay and vijay play a game of throwing dice Ajay throws a pair of dice and records the doublets on the other hand vijay throws a pair of dice and records a total of atleast 10 the person who has the more probability is a winner find who wins the game
Answers
Answer:
total possible outcomes =36
ajay's favourable outcomes = 6
p(ajay winning)= 1/6
vijay's favourable outcomes = 6
p(vijay winning )=1/6
both has equal probability of winning
Step-by-step explanation:
both has equal chance
The game is tied between Ajay and Vijay.
The total number of possible outcomes while throwing a pair of dice = 36
For Ajay -
He records the number of doublets, the possible doublets are (1,1) , (2,2) , (3,3) , (4,4) , (5,5) , (6,6) .
Total favourable outcomes = 6
probability = 6/36 = 1/6
For Vijay -
He records the number a total of atleat 10 , the number of possible outcomes are (6,4) , (4,6) , (5,5) , (6,6) , (5,6) , (6,5) .
Total favourable outcomes = 6
probability = 6/36 = 1/6
The probability of both Ajay and Vijay is the same , therefore the game is tied between them.