Math, asked by keshavbang13, 8 months ago

Ajay borrowed 20,000 from Balu at 10% p.a. simple
interest and twice that amount from Chetan at
20% p.a. simple interest. He then added an amount
of his own and lent the entire sum at 18% p.a.
simple interest. All the deals were for a year. At the
end of the year, he earned 4400. Find the amount
that he added.
(A) 15000. (B) 26000 (C) 24000 DX20000​

Answers

Answered by shrutisingh8055
1

Step-by-step explanation:

4400+2000+8000=60000+x 18/100

=20000

Answered by mychelsateam
3

Answer:

20,000

Step-by-step explanation:

Interest borrowed from Balu = PRT/100 = 20,000x10x1/100 = 2000

Interest borrowed from Chetan = PT x 2R/100 = 20,000x2x20x1/100 = 8000

Total interest he has to return = 8000+2000 = 10,000

Interest on his lending amount = PRT/100 = [20,000+40,000+y(amount he added)] x 18 x 1/100 = (60,000+y) x 18/100

Amount earned by him = [(60,000+y) x 18/100] - 10,000 (Interest he has to return)

4400 = [(60,000+y) x 18/100] - 10,000

y = 20,000

Note:

IN THE QUESTION WE ARE NEVER TOLD THAT HE'S RETURNING THE AMOUNT, SO IT'S ASSUMED THAT HE NEVER GAVE BACK THE WHOLE AMOUNT AND WE'RE CALCULATING HIS EARNING IN HAND FOR A YEAR

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