Math, asked by shivamindwar, 19 days ago

Ajay bought nine mobile phones for 8500 each. By mistake three of these were sold at a loss of 10% each. At what price should the remaining six mobile phones be sold to get a profit of 15%? What is the gain per cent at which each of the six mobile phones are sold?​

Answers

Answered by TheBestWriter
3

Solution-

Total CP of nine Mobile phones

= ₹(9×8500) = ₹76,500

If net gain on sale of 9 mobile phone = 15%, then, SP of nine Mobile phones

= CP + Gain = ₹ [76,500+(15/100×76,500)]

= ₹(76,500+11,475) = ₹ 87,975

Now, CP = ₹8500. If three mobile phones was sold at a loss of 10%, then

Loss = ₹(10/100×8500)=₹850

SP = CP - Loss = ₹(8500-850)=₹7650

The amount received on selling 3 mobiles phones at ₹7650 = ₹(3×7650) =₹22,950

Amount expected from the sale of remaining six mobile phones = ₹(87,975-22,950) = ₹65,025

SP of each of the remaining six mobile phones

= ₹(65,025/6) = ₹10,837.50

Thus, remaining 6 mobile phones should be sold at ₹10,837.50 each.

Gain on each mobile phone = SP - CP

= ₹10,837.50 - ₹8500 = ₹2337.50

Gain% for six mobile phones

= (Gain/CP ×100)%

= (2337.50/8500×100)%

= 27.5%

Hence, 27.5% of the six mobile phones are sold.

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