Question

ajay can complete a piece of work in 10 days. he works for 4 days and then khetan joins him and they together can complete the work in two days. how long can khetan working alone can complete the piece of work

the one to answer it correctly will be marked as brainliest.​

Answer 1

He will complete the work in 5 days if he work alone

Answer 2

GIVEN:

Ajay alone time to complete work = 10 days

he already worked for 4 days

khetan join after 4 days and both completed works in next two days.

To find:

let amount of work needed to be done is x

ajay work in one day is x/10 work.

therefore ajay completed work in four days is

4 × x/10

=4x/10

therefore remaining work is

x -4x/10

=6x/10

=3x/5

now assume that khetan alone doing these work in y days.

so khetan work speed in one day is x/y

so both together work

$\frac{3x}{5} = ( \frac{x}{10} + \frac{x}{y} ) \times 2$

$\frac{3}{5 } = ( \frac{2}{10} + \frac{2}{y} )$

$\frac{4}{10 } = \frac{2}{y}$

$y = 5$

Solution:

so khetan alone can complete piece of work in 5 days.