Question

Ajay can complete a piece of work in 4 days. balu takes double the time taken by ajay, charan takes double that of balu, and danush takes double that of charan to complete the same task. they are paired in groups of two each. one pair takes two thirds the time needed by the second pair-to complete the work. which is the first pair?

Answer 1

A= 1/4
B= 1/8
C= 1/16
D= 1/32

AD = 1/4 + 1/32 = 9/32
BC = 1/8 + 1/16 = 3/16

2/3 of AD = (2/3) * (9/32)
= 3/16
= BC
So the first pair is BC

Answer 2

Answer:

Step-by-step explanation:

ajay complete his work in 4 days .

so balu complete his work in 8 days

and charan takes 16 days and dhanush complete his work 32 days.

so daily work of each person is $\frac{1}{4},\frac{1}{8},\frac{1}{16},\frac{1}{32}$

we can check by hit and trial method

work of ajay and dhanush together is = $\frac{1}{4}+\frac{1}{32}=\frac{9}{32}$

work of balu and charan together= $\frac{1}{8}+\frac{1}{16}=\frac{3}{16}$

check the condition that is satisfy or not

$\frac{2}{3}$ (ajay and dhanush work)= (balu and charan work)

⇒$\frac{2}{3}*[\frac{9}{32}]=\frac{3}{16}\\\\\frac{3}{16}=\frac{3}{16}$