Question

Ajay can do a piece of work in 15 days and Binay can do the same work in 25 days. Binay worked on it for 10 days and then leaves. Ajay alone will finish the remaining work in :​

Answer 1

Answer:

(ajay+binay)'s 1 day work=1/15+1/25

=16/150

10 day's work of binay=2/5

ajay do remaining work in 5/3×1/15

=9days

Answer 2

Answer:

(9)

step by step=a×15=b×2o= total work .

then ; a:b= 2o:15 = 5:3

then the efficiency of Ajay (a) is 5;Vinay(b) is (3).

now

Total work is efficiency×time.

5×15=75.

1. Binay worked for 1o.(days).

t.w-comleted work.=remaining work.

• 75-3×1o=45.
• (45÷5=9.)