Question

Ajay can do a work in 16 days. He starts the work, works for 4 days and quits. Then Peter
takes over and does the remaining work. If Peter alone takes 24 days to do the entire work then In how many days will the work be completed?

Anyone who is able to solve this will be marked the Brainliest answer...
ALL THE BEST GUYS !!!

Answer 1

Answer:

22 days

Step-by-step explanation:

(i) Ajay can do a work in 16 days.

So, Work done by Ajay in 1-day = (1/16).

(ii) Given that he works for 4 days.

So, work done by Ajay in 4-days = (4/16) = 1/4.

Now,

Given that Peter does the remaining work.

Amount of work peter has do = 1 - (1/4)

                                                 = 3/4.

Peter alone takes 24 days to do the entire work.

= (3/4) * 24

= 18 days.

In the beginning, peter works for 4 days and quits.

So, the total work = 4 + 18 = 22 days.

Therefore, In 22 days work will be completed.

Hope it helps!

Answer 2

Answer:

$\boxed{\bf{\green{22}}}$

Step-by-step explanation:

Ajay can do a work in 16 days .

This means that Ajay can do 1 work in 16 days .

Ajay can do 1/16 th part of the work in 1 day .

So in 4 days he can do 1/16 th × 4 = 1/4 th of the work .

Thus 1/4 th portion of the work is done .

Peter takes 24 days to complete the work .

This means that Peter does 1 work in 24 days .

Peter will complete 1/24 th part of the work in 1 day .

Remaining work is ( 1 - 1/4 ) th

⇒ ( 4 - 1 )/4 th

⇒ 3/4 th part .

Hence 3/4 th part of the work is remaining .

Now Peter does 1/24 th of the work in 1 day .

Let him take n days to complete the work .

Then the part of the work done in n days = n × 1/24

⇒ n/24

According to the problem :-

n/24 = 3/4

⇒ n = 24 × 3/4

⇒ n = 6 × 3

⇒ n = 18

Hence Peter took 18 days .

Ajay also took 4 days .

∴ Days needed to complete the work = 18 + 4 = 22 days .

∵ 22 days are required to complete the work .